++ 50 ++ 3−5 346585-3 500l

 Tanner Stage 5 334−1370 Female RangesLet A = diag3, −5, 7 and B = diag−1, 2, 4 Find 2A 3B Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get• (𝑥𝑥5)3= 𝑥𝑥15 Rational Numbers A rational number is a number that can be expressed as a simple fraction (or ratio) 𝑝𝑝 𝑞𝑞 of two integers, 𝑝𝑝 and 𝑞𝑞, with 𝑞𝑞≠0 • 075, –6, √25, 008 , and are rational because they can be written as simple fractions 3 4,− 6 1, 5 1, 8 99, and

Ex 6 1 18 Solve 5x 3 3x 5 Show Solution On Number

3 500l

3 500l-C) −8sin(4x) 12 3x−1 63 5(3x1)8/5;Steps for Solving Linear Equation 5t3 = 3t5 5 t − 3 = 3 t − 5 Subtract 3t from both sides Subtract 3 t from both sides 5t33t=5 5 t − 3 − 3 t = − 5 Combine 5t and 3t to get 2t Combine 5 t and − 3 t to get 2 t

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Rationalize the denominator and simplify (i) √3−√2 √3√2 (ii) 52√3 74√3 (iii) 1√2 3−2√2 (iv) 2√6−√5 3√5−2√6 (v) 4√35√2 √48√18 (vi) 2√3−√5 2√23√33 −, and 8 3 − is a negative rational number So, 8 −3 is a negative rational number Similarly , 5 6 2, , − − −7 5 9 etc are all negative rational numbers Note that their numerators are positive and their denominators negative l The number 0 is neither a positive nor a negative rational number l What about 3 5 − −?(−)cis3,3′,4′,5,5′,7Hexahydroxyflavane3gallate, EGCG, (−)Epigallocatechin gallate, (−)cis2(3,4,5Trihydroxyphenyl)3,4dihydro1(2H)benzopyran

If A (5, 3), B (1 1, − 5) and P (1 2, y) are the vertices of a right angled triangle, right angled at P, then y is _____ AUnderstand Pre Calculus, one step at a time Enter your Pre Calculus problem below to get step by step solutions Enter your math expression x2 − 2x 1 = 3x − 5It is given that 5 − 3 5 3 = ab 15 Simplify the term on the LHS by rationalizing,5 − 3 5 3 × 5 3 5 3 = ( 5 )2 −( 3 )2( 5 3 )2 = 5−3( 5 )2 ( 3 )2 2 5 3 = 2532 15 = 2 15 = 4 15 Now,4 15 = ab 15 ⇒ a = 4 and b= 1

Determine the product −444−7135−3−1 1−111−2−2213 and use it to Solve the system of equations x y z = 4 , x 2y 2x = 9 , 2x y 3z = 1(CF 2) 7 CF 3 = R f8 are oxidized to aldehydes O=CH(CH 2) m −1 R f8 (Dess−Martin reagent, 90−96%), which are condensed with NH 2 CH 2 C 6 H 5 and Na(AcO) 3 BH to give benzylamines NH(CH 2 C 6 H 5)(CH 2) m R f8 (excess amine, −90%) or N(CH 2 C 6 H 5)(CH 2) m R f8 2 (excess aldehyde, 85−5 Calculate the value of 𝑓𝑓(−1),𝑓𝑓(−5), and 𝑓𝑓(2), given 𝑓𝑓(𝑥𝑥) = 𝑥𝑥𝑖𝑖 𝑥𝑥𝑓𝑓≤−3 𝑥𝑥2 𝑖𝑖−𝑓𝑓3 < 2 4 𝑖𝑖 𝑥𝑥𝑓𝑓≥2

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B) −10sin(5x)15e 3x1 − 4 (x−1);−36 1−5 5 −10 −4 −1 rref(A)= 1 −3 00 14 00 00 Use this to find all solutions of 2x1 −4x2 −x3 =2 −3x1 6x2 x3 = −5 5x1 −10x2 −4x3 = −1 and express your answer in vector form Thinking of the rowreduced matrix as an augmented matrix we see that there is no restriction on x2,so let x2 = s Piecewise functions are functions that have multiple pieces, or sections They are defined piece by piece, with various functions defining each interval Piecewise functions can be split into as many pieces as necessary Each piece behaves differently based on the input function for that interval Pieces may be single points, lines, or curves

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 JO AA 8/15/19 ii Table of Contents Paragraph Page 2−3−2 AREA/ROUTE BRIEFING PROCEDURES 2 −3−1 2−3−3Steps for Solving Linear Equation y = 5x3 y = − 5 x 3 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 5x3=y − 5 x 3 = y Subtract 3 from both sides Subtract 3 from both sides3−λ−−− =λ2−5λ=λ(λ−5) The only values ofλthat satisfy the equation det(A−λI2) = 0 areλ= 0 andλ= 5 Thus the eigenvalues ofLare 0 and 5 An eigenvectorof 5, for example,will be any nonzero vectorxin the kernel ofA−5I2

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Solving Rational Equations

3 2−4i 5i 5i Try it Now 1 Subtract 2 5i from 3− 4i real imaginary Section Polar Form of Complex Numbers 529 We can also multiply and divide complex numbers Example 4 Multiply 4(2 i5 ) To multiply the complex number by a real number, we simply distribute as we would Davneet Singh is a graduate from Indian Institute of Technology, Kanpur He has been teaching from the past 10 years He provides courses for Maths and Science at TeachooLamb E (14), "Does 123Really Equal –1/12?", Scientific American Blogs This Week's Finds in Mathematical Physics (Week 124), , , Euler's Proof That 1 2 3 ⋯ = −1/12 – by John Baez;

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View Homework 11docx from MATH 401 at Cosumnes River College 21 6∗109∗30 ¿ ¿ 330 ¿ 69 ¿ 15 330 ¿ 15 ¿ 22 24 4 (1) 3(−1) 6(2)3(−5) ¿ 4−312−15 M x =−2 4−3 5 = −35 5 (−3)2 = 2 5 9 It gets a bit tiresome to write both parentheses and brackets, so from now on we will dispense with the parentheses and just write T −3 5 = 2 5 9 At this point we should note that you have encountered other kinds of transformations For example, taking the derivative of a function results in another functionGet 5(2/3) 0 z = 4, so z = 4−10/3 = 2/3 Thus another point is (2/3,0,2/3) You can check that these points work in both equations Now we can use the standard line method (c) A position vector r0 = h0,5,−1i (d) A direction vector v = h2/3 −0,0 −5,2/3 −(−1)i = h2/3,−5,5/3i

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Solutions To Homework Assignment 5

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